2xy-3y^2+1=0

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Solution for 2xy-3y^2+1=0 equation:


Simplifying
2xy + -3y2 + 1 = 0

Reorder the terms:
1 + 2xy + -3y2 = 0

Solving
1 + 2xy + -3y2 = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 2xy + -1 + -3y2 = 0 + -1

Reorder the terms:
1 + -1 + 2xy + -3y2 = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 2xy + -3y2 = 0 + -1
2xy + -3y2 = 0 + -1

Combine like terms: 0 + -1 = -1
2xy + -3y2 = -1

Add '3y2' to each side of the equation.
2xy + -3y2 + 3y2 = -1 + 3y2

Combine like terms: -3y2 + 3y2 = 0
2xy + 0 = -1 + 3y2
2xy = -1 + 3y2

Divide each side by '2y'.
x = -0.5y-1 + 1.5y

Simplifying
x = -0.5y-1 + 1.5y

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